36x=2x^2+2x+40

Solution for 36x=2x^2+2x+40 equation:

36x=2x^2+2x+40

We move all terms to the left:

36x-(2x^2+2x+40)=0

We get rid of parentheses

-2x^2+36x-2x-40=0

We add all the numbers together, and all the variables

-2x^2+34x-40=0

a = -2; b = 34; c = -40;
Δ = b2-4ac
Δ = 342-4·(-2)·(-40)
Δ = 836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{836}=\sqrt{4*209}=\sqrt{4}*\sqrt{209}=2\sqrt{209}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-2\sqrt{209}}{2*-2}=\frac{-34-2\sqrt{209}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+2\sqrt{209}}{2*-2}=\frac{-34+2\sqrt{209}}{-4}
$